a=-0.5

Speed = 90km/h find distance

### Asked by mrohitgarg2008 | 24th May, 2021, 09:02: AM

Expert Answer:

### The question is assumed that initial speed is 90 km/hr, deceleration is 0.5 m/s^{2} and what is the distanace travelled.
We need to use equation of motion " v^{2} = u^{2} - ( 2 a S ) " , where v is final speed and u is initial speed. Final speed v is zero because the object comes to rest after travelling a distance S with deceleration a .
S = u^{2} / ( 2 a ) ..................... (1)
Speed 90 km/hr = 90 × ( 5 / 18 ) = 25 m/s
S = ( 25 × 25 ) / ( 2 × 0.5 ) = 625 m

^{2}and what is the distanace travelled.

^{2}= u

^{2}- ( 2 a S ) " , where v is final speed and u is initial speed. Final speed v is zero because the object comes to rest after travelling a distance S with deceleration a .

^{2}/ ( 2 a ) ..................... (1)

### Answered by Thiyagarajan K | 24th May, 2021, 09:13: AM

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